Arturo O. answered • 09/05/17
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Do you mean ORBITAL quantum number L = 1? The electrons in p orbitals have L = 1. From the electronic configuration of Te (Z = 52), find how many electrons are in p orbitals, and that will be your answer. The electronic configuration of Te is
1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p4
There are 6 + 6 + 6 + 4 = 22 electrons in p orbitals.
Arturo O.
J.R. S.,
In physics textbooks it is refereed to as the orbital quantum number, to distinguish it from the magnetic quantum number associated with the z-component of the orbital angular momentum. I used upper case L because the lower case l looks too much like the number 1. The L in my explanation is the same as the l in your explanation, with the L coming from the eigenvalue of the square of the angular momentum operator. Here I will use upper case L for the operator and lower case l for the quantum number:
L2ψ = h_bar2 l(l + 1)Ψ
Lzψ= h_barmψ
m = magnetic quantum number
h_bar = h/(2π)
and of course, Ψ is the wave function.
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09/06/17
Arturo O.
And m can have integer values from -l to l.
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09/06/17
J.R. S.
tutor
Ah...got it. Crossover of physics and chemistry. Who knew? Thanks.
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09/06/17
Arturo O.
I just want to add:
I actually like the way they present quantum mechanics (QM) in chemistry books more than in physics books. Too often, the physics QM books get so deep into the mathematical formulation and get so abstract, that it seems they lose touch with the physical objects being modeled. In chemistry QM books, I noticed the authors "stay in touch" with atoms, molecules, ions, and other neat things, and they are much more conceptual, which makes it easier to grasp the material.
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09/06/17
J.R. S.
tutor
Agreed. Thanks for your participation.
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09/06/17
J.R. S.
09/06/17