My son has a math problem: If a trapezoid has 2 right angles, what are the other 2 (ex accute and obtuse).
My son has a math problem: If a trapezoid has 2 right angles, what are the other 2 (ex accute and obtuse).
Draw an imaginery line to form a rectangle at the opposite end of the two right angles, within the trapezoid. This will give you an imaginary rectangle and an imaginary right triangle within your trapezoid. The sum of all angles in a triangle is 180 degrees. Just wanted to drop in another way of looking at the problem as most math problems have more than one way of finding the answer... If you are looking for actual values to those angles: Assuming you have at least 3 lengths of your trapezoid: use sin(angle)= opposite/hypotenuse; cos(angle)= adjacent/hypoteneuse; or tan(angle)= opposite over adjacent. Use the imaginary triangle you created, pick one of the odd angles, and your hypoteneuse will be the longest side of your triangle.
Yes one angle would be acute ( less than 90) and the other would be obtuse ( greater than 90 degress) however those two angles would add up to 180 degrees. In a trapezoid you must have 2 parallel lines and 2 nonparallel lines wish I could draw this. In order to figure out the degrees of the other 2 angles I would need more info. /___l imagine a straight line going across the top too. The right top and bottom angles are 90 degrees and the top and bottom lines are parallel . The top left angle is acute and bottom left is obtuse the vertical left and right lines are not parallel . Hope this helps :)
Comments
I'm voting 1.5 times for John's answer b/c
1. it is elegant and uses few words and
2. b/c he costs the least, but David, like an engineer, drew us apicture that helps explain the basic trapezoidal properties.
My answer, when in hS, would have been:
"They are any two complementary angles that add up to 180, except 90 and 90."