Dr Gulshan S. answered 08/30/17
Tutor
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(52)
PhD In Physics and experience of teaching IB Physics and Math High sc
Hi Boni
Electric field of a charged ring is given as ( For the one at origin field will be zero Ez0 =0)
Ez= KQz/ ( w2 +z 2) 3/2
Case 1 : when ring is not very small in radius w= radius of ring and z = distance of center ring from the origin
Ez1= KQw/(w2 +w 2) 3/2
Ez2 = KQ(2w)/(w2 +4 w 2) 3/2
Ez3 = KQ(3w) / (w2 +9w 2) 3/2
and so on.... add this sequence
Case 2 For small radius
Ez1 = KQ/w 2
Ez2 = KQ/4w 2
Ez3 = KQ/9w 2
and so on....
Add this sequence
Case 3 ( Applicable to both)
When the charged rings are place on both sides ( +z and -z)
The net Electric field at the origin will be zero.