R J.

# Is there a number to "a" such that the limit exists? If so, find the value of "a" and find the limit. If not, explain why.

Find the limit as "x" approaches 3
F(x)= (2x2-3ax+x-a-1)/ x2-2x-3
**I already know that if you substitute in 3 for x, the denominator will be 0 and therefore it cannot exist. I'm wondering if someone can find a way to factor it so that there can be a hole or removable discontinuity and therefore the limit may be able to exist.

Mark M.

Please check the signs on the "a" and the "1."
Report

08/26/17

Arturo O.

Is the numerator

2x2 - 3ax + x - a - 1

correctly stated?  Having 2 terms with x looks strange.  Please check the original problem.
Report

08/26/17

## 2 Answers By Expert Tutors

By:

Tutor
5.0 (66)

Experienced Physics Teacher for Physics Tutoring

Tutor
5.0 (399)

20+ years teaching Calculus

## Still looking for help? Get the right answer, fast.

Get a free answer to a quick problem.
Most questions answered within 4 hours.

#### OR

Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.