R J.

asked • 08/26/17

Is there a number to "a" such that the limit exists? If so, find the value of "a" and find the limit. If not, explain why.

Find the limit as "x" approaches 3
F(x)= (2x2-3ax+x-a-1)/ x2-2x-3
**I already know that if you substitute in 3 for x, the denominator will be 0 and therefore it cannot exist. I'm wondering if someone can find a way to factor it so that there can be a hole or removable discontinuity and therefore the limit may be able to exist. 

Mark M.

tutor
Please check the signs on the "a" and the "1."
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08/26/17

Arturo O.

Is the numerator 
 
2x2 - 3ax + x - a - 1 
 
correctly stated?  Having 2 terms with x looks strange.  Please check the original problem.
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08/26/17

2 Answers By Expert Tutors

By:

Arturo O. answered • 08/26/17

Experienced Physics Teacher for Physics Tutoring

Victoria V. answered • 08/26/17

20+ years teaching basic Calculus & beyond.

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