J.R. S. answered 08/09/17
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Let's take your example of CaCO3(s) + H2SO4(aq) → CaSO4(s) + CO2(g) + H2O(l) (unbalanced)
The H2SO4 has to be aqueous (aq) because all acids are aqueous, otherwise they aren't really acids. The CaCO3 is solid (s) and you know this because it is insoluble. The CaSO4 is also insoluble, so is (s). The CO2 is, of course, a gas (g) and finally the H2O is liquid (l) at room temperature. If this were a combustion, then the H2O formed could be a gas (g). So, in summary, one needs to KNOW what compounds are soluble (aq) and which are insoluble (s). You know this from the solubility rules. One also must KNOW which are gases (g). Obviously, CO2, CO, O2, N2, H2, etc. will all get (g) notations. As for H2O, it will be (l) most times, but can be (g) if temperature and pressure allow.
Just for the record, H2SO4 is molecular, made from covalent bonds (no ionic bonds are present). Pure H2SO4 is a viscous liquid, but isn't really acidic until added to H2O. Just like HCl is naturally a gas (g) but become acid when placed in water as HCl(aq). I hope this helps explain some of the confusion.
J.R. S.
tutor
CH2O is an empirical formula and different compounds with that same empirical formula can and will have different properties. Whoever said the properties are the same is incorrect.
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08/09/17
Tommer Z.
08/09/17