Ronald B. answered 08/08/17
Tutor
New to Wyzant
SAT/ACT, Math, and Science Tutor
This can be solved by using the completing the square method.
First, I am going to subtract the 14 from each side to get:
x2+y2+14x + 2y = -14
Now let's focus on the y's and then we can apply the same logic to the x's. For simplicity, I am going to put stuff with x variables aside, but we are going to figure out both coordinates in a bit.
y2+2y= -14
using the completing the square we must divide the coefficient in front of the y by 2, in this case, we use the 2y and then square it. 2/2 = 1, 12= 1. add this 1 to both sides of the equation.
y2+2y + 1= -14 + 1
This yields
y2+2y + 1= -13. Now, we factor the left side of the equation. We get (y+1)*(y+1) = -13 aka (y+1)2 = -13
y2+2y + 1= -13. Now, we factor the left side of the equation. We get (y+1)*(y+1) = -13 aka (y+1)2 = -13
ok we figured out the shift in the y axis for the center of the circle, now it is time to do it for the x's. I am going to keep the -13 in this case because when we use the completing the square method, we have to add to the right side of the equation when we solve for the x and y shift of the center.
x2 + 14x = -13. Now we do the same method we did previously for y. 14/2 = 7, 72 = 49. let's add that 49 to each side of the eqn.
x2 + 14x = -13. Now we do the same method we did previously for y. 14/2 = 7, 72 = 49. let's add that 49 to each side of the eqn.
x2 + 14x +49 = -13 + 49 This gives us: x2 + 14x +49 = 36. Factor out the left side of the equation like before, you get (x+7)2 = 36
PUTTING IT ALTOGETHER:
(x+7)2 + (y+1)2 = 14 + 1 (from solve for y) + 49 (for solving for x). We get (x+7)2 + (y+1)2 = 36.
(x+7)2 + (y+1)2 = 14 + 1 (from solve for y) + 49 (for solving for x). We get (x+7)2 + (y+1)2 = 36.
This equation is now in center-radius form. your center is -7,-1 and your radius is 6.
If you are not sure how I got that last part, this is because the typical equation is formatted in this way:
(x-h)2 + (y-k)2 = r2
If you are not sure how I got that last part, this is because the typical equation is formatted in this way:
(x-h)2 + (y-k)2 = r2
x,y is any point on the circle
h,k is the center (switch signs when moving from the actual coordinates to the eqn form.)
h,k is the center (switch signs when moving from the actual coordinates to the eqn form.)
r is the radius
If you have any more questions let me know!
y2+2y + 1= -14 + 1