J.R. S. answered 07/29/17
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(111)
a) XyPh
b) Xy2Ph3
c) Xy2Ph4 = XyPh (empirical)
d) XyPh2
(112)
a) Xy = 2+; Ph = 2-
b) Xy = 3+; Ph = 2-
c) Xy = 2+; Ph = 2-
d) Xy = 4+; Ph = 2-