
Arturo O. answered 07/18/17
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Degree 4 means you need 4 zeros. Real coefficients means that if you have a complex zero, its complex conjugate must also be a zero.
So far,
f(x) = a(x - 2)(x + 4/3)([x - (2 - 3i)][x - (2 + 3i)],
with a real and a ≠ 0.
Note that
[x - (2 - 3i)][x - (2 + 3i)] = x2 - (2 + 3i)x - (2 - 3i)x + (22 + 32) = x2 - 4x + 13
f(x) = a(x - 2)(x + 4/3)(x2 - 4x + 13)
To find a, you need to know the value of y at some x. I am not sure what you mean by "f has a y-integer of 52." Could you check the original problem statement and see if it gives an (x,y) pair?