Pleeeease Help!!

Question

 To the nearest tenth, find the perimeter of ΔABC with vertices A(2,4), B(-2,1) and C(2,1). Show your work.

Answer 1

use the distance formula: √[(x₁-x₂)²+(y₁-y₂)²]

A(2,4), B(-2,1)

√[(2+2)²+(4-1)²]

√[4²+3²]

√[16+9]

√25

5

 

B(-2,1), C(2,1)

√[(-2-2)²+(1-1)²]

√[(-4)²+0²]

√(16

4

 

C(2,1), A(2,4)

√[(2-2)²+(4-1)²]

√[0²+3²]

√9

3

perimeter=3+4+5

perimeter=12 units

Answer 2

It will help you greatly to plot those three vertices and then to draw the triangle.

You will see that distance AC = 3.  Then, I imagine, that you can see that the distance BC = 4.

With a little bit of thought, you will solve this whole problem.