quadratic formula #10

Question

The question is, solve the equation using the quadratic formula

 

5x²+2x-3=0

Answer 1

If this is the question:  5X²+2X-3=0 then the answer is simple:

 

quadratic formula is that for an equation with the form aX²+bX+c=0 then X=(-b+/- sqroot(b²-4.a.c))/2.a

 

so the answer would be  X=(-2+/- sqroot(4-4(5)(-3)))/10

 

4-4(5)(-3)=64 and sqroot(64) = 8 then...

 

X= (-2+/-8)/10 you'll have 2 solutions:

 

X1 = (-2+8)/10 = 6/10 = 3/5

 

X2 = (-2 - 8)/10 = -10/10 = -1