Remember that for any quadratic equation:
ax^2+bx+c = 0
The quadratic formula says that the two solutions will be:
x = b/2a ± sqrt(b^24ac)/2a
What are a, b and c in this case?
Try substituting in the numbers from your problem and seeing if you can work it out. If you have trouble let me know and I will do my best to help.
Jun 12

Jose S.
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