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Temperature conditions at the arctic pole changed from -15°F to

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1 Answer

Hi Missy,
 
"percent change" is
 
    100 * amount of change / initial value, or
 
    100 * (initial value - final value) / initial value
 
We could say, therefore, that the percent change (in °F or Fahrenheit) is
 
    100 * (-15 - -30) / -15  =  100 * (-15 + 30) / -15  =  100 * 15 / -15  = -100
 
The change is -100%; that is, a decrease of 100% (because the - sign means "decrease").
 
This answer is fine, but not the best one. There is a big problem using Fahrenheit for calculating % change ... suppose that it was a bit warmer at the arctic that day, and instead if changing from -15 to -30°F, it changed from 0 to -15°F. We calculate %change as
 
    100 * (0 - -15) / 0
 
Oh no -- division by 0 is not allowed ! We cannot give any answer. Therefore, it is better to use an "absolute" temperature scale to calculate %change. An absolute temperature scale is a scale where the coldest anything could ever be is 0. One such scale is the Rankine (R). The relationship between R and °F is
 
   R = °F + 459.67
 
We need to convert -15°F and -30°F to R, and then calculate 100 * (initial value - final value) / initial value.
 
I'll let you do that ! But I give you a hint - the answer is very different from the -100% we got above.