
PIYUSH L. answered 06/03/14
Tutor
5
(6)
Maths tutoring for middle school to college maths students
Hi Jennie,
When a plane passes through a sphere, the resultant cross section formed is a circle. If you try to think over it, you can easily deduce the radius of that circle as Square-root(y^2-x^2) ( Try thinking it as a right triangle with hypotenuse y unit and the other two sides as x and the radius of the cross-sectional circle)
Therefore the cross-sectional area will be π*(y^2-x^2) as area of a circle with radius r is π*r^2