Arthur D. answered 06/02/14
Tutor
4.9
(286)
Forty Year Educator: Classroom, Summer School, Substitute, Tutor
slant height
62+82=(Hs)2 where Hs is the slant height
36+64=(Hs)2
100=(Hs)2
Hs=10 m
volume
V=(1/3)*pi*r2*h
V=(1/3)*3.14*62*8
V=(1/3)*3.14*36*8
V=3.14*12*8
V=3.14*96
V=301.44 cubic meters
surface area
lateral surface area=(1/2)*circumference*slant height
lateral surface area=(1/2)(2*pi*r)*10
lsa=pi*6*10
lsa=3.14*60
lsa=188.4 sq m
now find the area of the circular base
A=pi*r2
A=3.14*62
A=3.14*36
A=113.04 sq m
now add the lateral surface area and the area of the base
total surface area=188.4+113.04
total surface area=301.44 sq m