(to the nearest whole meter) having a radius of 6 m and height of 8 m.

^{2}+8

^{2}=(Hs)

^{2}where Hs is the slant height

^{2}

^{2}

^{2}*h

^{2}*8

^{2}

^{2}

Find the slant height of a cone

(to the nearest whole meter) having a radius of 6 m and height of 8 m.

(to the nearest whole meter) having a radius of 6 m and height of 8 m.

Find the volume and the surface area of the above cone rounded to the nearest

tenths.

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slant height

6^{2}+8^{2}=(Hs)^{2} where Hs is the slant height

36+64=(Hs)^{2}

100=(Hs)^{2}

Hs=10 m

volume

V=(1/3)*pi*r^{2}*h

V=(1/3)*3.14*6^{2}*8

V=(1/3)*3.14*36*8

V=3.14*12*8

V=3.14*96

V=301.44 cubic meters

surface area

lateral surface area=(1/2)*circumference*slant height

lateral surface area=(1/2)(2*pi*r)*10

lsa=pi*6*10

lsa=3.14*60

lsa=188.4 sq m

now find the area of the circular base

A=pi*r^{2}

A=3.14*6^{2}

A=3.14*36

A=113.04 sq m

now add the lateral surface area and the area of the base

total surface area=188.4+113.04

total surface area=301.44 sq m

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