Hediye G. answered 05/05/14
Tutor
New to Wyzant
Assuming that v= 5 + 75/(1+e^-((t-50)/10))
Replace v and t and you get
t= 5 + 75/1+e^-((v-50)/10)
then solve it for v
subtract 5 from both sides, multiply by 1+e^-((v-50)/10) and divide by (t-5)
you get
1+e^-((v-50)/10)=75/(t-5)
Subtract 1 from both sides and take natural log of both sides and you get
-((v-50)/10=ln(((75/(t-5))-1)
Multiply by -10 and then add 50
and you end up with
v=50-10ln(((75/(t-5))-1)