how do I write in logarithmic form using (1/2)^4 - 1/16

I have log 16 = 2

thanks

how do I write in logarithmic form using (1/2)^4 - 1/16

I have log 16 = 2

thanks

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Sandy Spring, MD

Are you sure of the problem? As this is written, log 16 = 2, means that the log base is 10, and 10^2 = 16. I think this may be log_{b}16 = 2, or b^{2} = 16. Is this correct?

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