Benjamin,
Here we go!
First off, the tensile force use to gravity is mass in kg times g or 400g.
Then, the cross sectional area is pi times radius squared or .012^2*3.14
We can see from units of stress that we have to divide the tensile force found in part a in newtons by the cross sectional area in meters squared found in part b.
Now de young's modulus is the ratio of stress to strain, so divide the stress found in part c by 200*109.
To find the original length after stretching .78mm you need to use the formula relating tensile force to length:
F=EAΔL/L0 where E is the modulus, A is the cross sectional are from part b,and F is the force from part a. Plug in .07 for delta L and solve for L0.
Hope that helps!
Deanna