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Solving trig identities

No restrictions on Θ.
 
2cosΘ-1=0
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3 Answers

2cosΘ-1=0
 
2cosΘ = 1
 
cosΘ = 1/2 
 
cosΘ is positive in the first and 4th quadrant cosΘ = 1/2  at 60degrees and 300 degrees
or pi/3 rad and 5pi /3
Hi Chloe,
 
2cosθ-1=0
2cosθ =1
cosθ =1/2
 
θ =π/3 = 60° or θ=5Π/3 =300°
 
 
 
Meena from Strongsville,OH
cosθ=1/2, then θ=2kπ+π/6 or 2kπ-π/6 (k∈Z).