cos x * 2√3 = 0 What do I need to do to find X?

Question

I have been stuck on this one for a while. Can someone help me find x?

Answer 1

if you mean (cosx)(2sqr3) = 0 then

cosx = 0

x = arccos0 = pi/2 + pin where n = any integer

or in degrees

x = 90 + 180n where n = any integer

but maybe you meant cos(2xsqr3) = 0 ? if so then

2xsqr3 = 90

x = 90/2sqr3 = 45/sqr3 = 45sqr3/3 = 15sqr3 = about 15(1.732) = about 25.98 degrees

plus some number to capture an infinite number of solutions