Parviz F. answered • 04/04/14
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130 ^2 = 50^2 + b^2
b = √[(130^2) - (50^2) ] = √[ ( 16900- 2500) = √14400 = 120
Leticia F.
asked • 04/03/14I have a base of 50 and a hypoteneuse of 130 how do i solve for b
pythagorean therom I have a base of 50 + ahypoteneuse of 130 how do I solve for the other side
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