Ask a question

If the area of a rectangle is x2 + 7x + 12 square meters and the length and width of a second rectangle are 3 meters longer, what is the area of the second rect

Explain your reasoning.

1 Answer by Expert Tutors

Tutors, sign in to answer this question.
Kemal G. | Patient and Knowledgeable Math and Science Tutor with PhDPatient and Knowledgeable Math and Scien...
4.8 4.8 (5 lesson ratings) (5)
Hi Kiomye,
Let the area of the rectangle be A. Then, A =  x^2 + 7x + 12
A = (x+3)(x+4)   The factors are the dimensions of the rectangle.
Now, if we increase the dimensions by 3 meters, the new dimensions will be
(x+3+3) = (x+6) m and (x+4+3) = (x+7) m
The area of this rectangle, which I will call A2 will be
A2 = (x+6)(x+7)
= x^2 + 13x + 42 square meters