What is the percent yield? - Show Work Please

Question

Question: If the reaction of 20.7 grams of CaCO3 produces 6.81 grams of CaO, what is the percent yield?

 

Equation: CaCO3 = CaO + CO2

Answer 1

CaCO3 = CaO + CO2  Balanced equation

moles CaCO3 present = 20.7 g x 1 mole/100g = 0.207 moles 

theoretical yield of CaO = 0.207 moles CaCO3 x 1 mole CaO/mole CaCO3 = 0.207 moles CaO

theoretical mass of CaO = 0.207 moles x 56.1 g/mole = 11.6 g CaO

percent yield = actual yield/theoretical yield (x100%) = 6.81 g/11.6 g (x100%) = 58.7 percent