How do I solve this? y^2=-6x

Question

Find the vertex, focus, and directrix of the parabola, and sketch the graph. I think I use this formula but I'm not sure: (y-k)^2=4p(x-h)

Answer 1

y²=-6x

(y-k)²=4p(x-h)

(y-0)²=4(-3/2)(x-0)

vertex=(h.k)

vertex=(0,0)

 

focus=(h+p,k)

focus=(0+[-3/2],0)

focus=(-3/2,0)

 

directrix is x=h-p

x=h-p

x=0-(-3/2)

x=3/2