Using standard heats of formation, calculate the standard enthalpy change for the following reaction.

Question

C2H4(g) + H2O(g)CH3CH2OH(g)

Answer 1

C2H4(g) + H2O(g) ===> CH3CH2OH(g)

Given the following ∆H_f^o 

• C2H4(g) = 52.3 KJ/mole
• H2O(g) = -242 kJ/mole
• CH3CH2OH(g) = -201 KJ/mole

 

∆H_rxn = -201 - (52.3 + -242) = -201 - (-189.7)

∆H_rxn = -11.3 KJ/mole