What is the concentration of OH- in a solution if the pH is

Question

a. pH = 4.07

b. pH = 0.32

c. pH = 13.68

d. pH = 7.41

 

Answer 1

Recall pH + pOH = 14 and Kw = [H+][OH-] = 1x10^-14

a) pH = 4.07

   pOH = 14 - 4.07 = 9.93

   [OH-] = 1x10^-9.93 = 1.17x10^-10 M

 

b) pH = 0.32

   pOH = 14 - 0.32 = 13.68

   [OH-] = 1x10^-13.68 = 2.09x10^-14 M

 

c) pH = 13.68

   pOH = 14 - 13.68 = 0.32

   [OH-] = 1x10^-0.32 = 2.09x10^-1 M

 

d) pH = 7.41

   pOH = 14 - 7.41 = 6.59

   [OH-] = 1x10^-6.59 = 2.57x10^-7 M