J.R. S. answered 03/30/17
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To obtain an average rate of reaction, one can look at initial concentration of 0.8% and the final concentration of 0.4% and the overall time of 40 minutes. The ∆concentration/∆time = rate = 0.4%/40min = 0.01%/min = rate
It is first order because as the concentration changes from 0.8 to 0.67 to 0.56 etc. ,the rate stays the same, so it is directly related to the concentration. For example from 0 to 10 min rate is 0.13/10 min when conc. is 0.8 so 0.13/0.8 = 0.16. In the next time epoch, the conc. is 0.67 and goes to 0.56 so you have a rate of 0.11/10 min and 0.11/0.67 = 0.16, the same as previously. This shows it is first order with respect to the reactant.
rate = k[ ]
0.01 = k [0.8%]
k = 0.0125
It is first order because as the concentration changes from 0.8 to 0.67 to 0.56 etc. ,the rate stays the same, so it is directly related to the concentration. For example from 0 to 10 min rate is 0.13/10 min when conc. is 0.8 so 0.13/0.8 = 0.16. In the next time epoch, the conc. is 0.67 and goes to 0.56 so you have a rate of 0.11/10 min and 0.11/0.67 = 0.16, the same as previously. This shows it is first order with respect to the reactant.
rate = k[ ]
0.01 = k [0.8%]
k = 0.0125
Reaction rate at 30 minutes = (0.8 - 0.47)/30 min = 0.33%/30 min = 0.011%/min (virtually same as average rate of 0.01%/min).