You can use 2n to figure out the number of possible outcomes where n is the number of tosses. If n = 3, then there are 8 possible outcomes. For the tree diagram, the first toss will either be a head or a tail. The second and third tosses will give you the same choices, but you will have more combinations to deal with. The sample space will contain the possible combinations of getting heads and tails.
{HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}
A) P(3 tails) = 1/8 = 0.125
B) P(2 tails) = 2/8 = 0.25
C) P(at least 1 tail) = 7/8 = 0.875