Please help

Question

How much heat does it take to increase the temperature of 1.45 L of water from 0 deg Celsius to 100 deg Celsius? Assume water has a density of 1 g/mL

Answer 1

q = mC∆T

m = mass = 1.45 L x 1000 ml/L x 1 g/ml = 1450 g

C = specific heat of water = 4.184 J/g/deg

∆T = change in temperature = 100º - 0º = 100 degrees

q = (1450 g)(4.184 J/g/deg)(100 deg) = 606,680 J = 606.7 kJ = 607 kJ (to 3 significant figures)