
Amber N.
asked 03/16/17what is the ones digit?
What is the ones digit of 11^11+14^14+16^16? I also have to use the strategy "Solve a simpler problem". Can someone please help. Thanks!
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2 Answers By Expert Tutors

Andrew M. answered 03/16/17
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
With n>0:
11n will always have a 1's digit of 1
1111 has 1's digit of 1
14n will have 1's digit of 4 if n is odd
14n will have 1's digit of 6 if n is even
1414 has 1's digit of 6
16n will always have a 1's digit of 6
1616 has 1's digit of 6
1+6+6 = 13
The '1' from the 10's space will be carried in
your addition leaving 3 in the 1's digit space
of the sum.

David W. answered 03/16/17
Tutor
4.7
(90)
Experienced Prof
The strategy "the strategy 'Solve a simpler problem'" means that you identify sub-problems, solve them, then put those solutions together in order to solve the big problem.
This math problem seems to be: A + B + C
Problem A: What is 11^11 ??
This expands to: What is 11*11*11*11*11*11*11*11*11*!1*11?
11*11 = 121
Then 121 * 11 and the following partial sums (the running product) may be written as:
xxxxx1 [note: x is some digit]
* 11
------------
xxxxxx1 [note: the ones digit is always 1]
* 11
------------
xxxxxxx1 [note: the ones digit is always 1]
. . . [do this 11 times]
--------------------
xxxxxxxxxx1 [So, the ones digit for Sub-problem A is 1]
Now, the ones digit (the right-most digit) for Sub-problem C is always 6 [PLZ check this yourself].
But, watch out! The ones digit for Sub-problem B alternates between 6 (for even exponent) and 4 (for odd exponent),
so you must select the correct value, then add the ones digits for Sub-Problems A+B+C.
NOTE: The problem only asks for the ones digit of the grand sum (A+B+C).
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Camelia C.
03/16/17