Lily B.

asked • 03/12/17

Advanced Functions Help

the ferris wheel at an amusement park measures 16m in diameter. the wheel does 3 rotations every minute. the bottom of the wheel is 1m above the ground... a) determine the simplest equation that models Megan's height above that ground(h) over time (t). give 2 more equations that model the situation. please explain! :) is the period 0.3 or 20 mins? shouldnt it 0.3 because (1 revolution per a min

1 Expert Answer

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Hank L. answered • 03/12/17

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Lily B.

wait why is there frequency?  we learned it as f(x)= a sin/cos [k(x-d)]
max is 8, min is -8, so a = 8
period = 2pi/k = 20 sec
20k = 2pi
k = pi/10
 
 h = 8 sin [pi/10(t-5) ] + 9  is wrong?? 
 
 
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03/12/17

Hank L.

Hi Lily, 
So period and frequency are just inverses of each other:
f = 1/T
 
but ANGULAR frequency simply turns a linear value (how many times a thing goes back and forth per unit time) into a rotational value (how many circles it makes per unit time)
The equation is ω = 2πf
And since we said period is 1/f, then frequency must be 1/T
So ω = 2π/T
The period is 20 seconds.
 
Thus ω = 2π/20 = 0.1π and that's the value I used in the formulas

Hopefully this helps? Comment back if you're still stuck
 
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03/12/17

Lily B.

Yep that makes sense!!! but how would you do that as y= a sin/cos[k(x-d)]+c
cause that what we did in school, your method makes sense but my teacher would takes marks off for that. 
so when i converted it i got this so in this write?
i got pi/10 by doing 
period = 2pi/k = 20sec
20k = 2pi
k = pi/10
h=8 sin [pi/10(t-5)]+9 ??

Also how high is emily after 25 secs?? would it be 9? if i were to just sub in 25 into "t"? also when i put this equation on the graph it doesn't show 9 at 25sec.... on desmos
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03/12/17

Hank L.

aha, so I just answered (confirmed your answer) on your newest question. Without knowing more about the initial conditions (as in, what height is Emily at t=0), we can't predict her height 25 seconds later. Are you supposed to assume that she is at the bottom at t=0 because that's where she loads? But that wouldn't make sense either because she probably wouldn't immediately start going 3 revolutions per minute... so yeah, depending on where she is at t=0 will determine where she ends up at t=25 per the h(t) function you specify.
In other words, the initial condition sets the phase shift.
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03/12/17

Hank L.

per your message to me with the screenshot of the problem, ignore what I said about phase shift in this original answer. The phase shift DOES matter because in the problem from the screenshot, it assumes t=0 is when Emily gets on the ride at the lowest point and thus your phase shift of -5 is the correct one.
 
 
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03/12/17

Lily B.

oKay perfect thanks! So at 25 seconds she will be at 9 m if i were to sub 25 into t?
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03/12/17

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