Roman C. answered 03/13/17
Tutor
5.0
(851)
Masters of Education Graduate with Mathematics Expertise
a. ∇f(x,y,z,w) = 〈sin y + w cos x + 1, sin z + x cos y + 1, sin w + y cos z, sin x + z cos w〉
This means the following must all be f(x,y,z,w):
x sin y + w sin x + x + h1(y,z,w)
y sin z + x sin y + y + h2(x,z,w)
z sin w + y sin z + h3(x,y,w)
w sin x + z sin w + h4(x,y,z)
We see that these expressions can be made equal. You get:
f(x,y,z,w) = x sin y + w sin x + z sin w + y sin z + x + y + C
b. ∇f(x,y,z,w) = 〈yz, xz, xy, yw〉
This means the following must all be f(x,y,z,w):
xyz + h1(y,z,w)
xyz + h2(x,z,w)
xyz + h3(x,y,w)
yw2/2 + h4(x,y,z)
If there was an f(x,y,z,w), then we see that yw2/2 would have to be in the definition of h2(x,z,w). Therefore it doesn't exist.