
Arturo O. answered 03/11/17
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1 - 1/cos2β = (cos2β - 1) / cos2β = -(1 - cos2β) / cos2β = -sin2β / cos2β = -tan2β
Sara M.
asked 03/11/17Arturo O. answered 03/11/17
Experienced Physics Teacher for Physics Tutoring
1-1/cos^2 B =(cos^2 B - 1)/cos^2 B =-sin^2 B / cos^2 B =-tan^2 B
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