Ben T. answered 03/10/14
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Experienced Math Tutor (From Algebra to Calculus)
Multiply the third equation by (-5/3) and add to the first equation to cancel out x and z:
5/4x -4/3y +5/4z = 6
-5/4x +5/3y -5/4z = -10
Leaving you with 1/3y = -4 => y = -12
Plug -12 in for y in either the first or third equation and solve for x in terms of z:
5/4x -4/3(-12) +5/4z = 6
5/4x + 5/4z = -10
x = -z - 8
Plug (-z - 8) in for x and -12 in for y in the second equation and solve for z:
5/16(-z - 8) +5/4(-12) -4/16z = -4
-9/16z - 5/2 - 15 -4/16z = -4
-9/16z = 27/2
z = -24
x= 16
y= -12
z= -24