there are 4 white mice and 6 brown mice in a cage. Molly will take out 2 mice at random. If the first mouse she takes out is brown.

a. 2/5

b. 4/9

c.1/2

d.4/5

there are 4 white mice and 6 brown mice in a cage. Molly will take out 2 mice at random. If the first mouse she takes out is brown.

a. 2/5

b. 4/9

c.1/2

d.4/5

Tutors, please sign in to answer this question.

Olney, MD

After taking out the first mouse (a brown one), there are 9 mice remaining in the cage, 4 white ones and 5 brown ones. The probability, then, that the second mouse will be a white one is computed as follows:

P = (Number of White Mice Remaining in the Cage) / (Total Number of Mice Remaining in the Cage)

Let me know what you get.

Willowbrook, IL

Notice that the answer will depend on the manner she takes mice out. If she takes them one after another, then Robert's answer is correct. If she takes both together (with two hands, for example) then the probability is:

6/10*4/9=4/15

Wesley L.

Premier MIT Math Tutor and SHSAT/SAT/ACT Specialist

New York, NY

5.0
(199 ratings)

Jason L.

Top scoring professional SAT and ACT tutor; Practicing Attorney

Livingston, NJ

5.0
(8 ratings)

- Math Help 3959
- Algebra 3731
- Calculus 1703
- Math Word Problem 2781
- Algebra 2 2685
- Word Problem 3735
- Algebra 1 3019
- Math Equations 841
- Math Help For College 1149
- Math Problem 718

Find a tutor fast. Get the app.

Are you a tutor? Get the app for tutors

© 2005 - 2016 WyzAnt, Inc. - All Rights Reserved

## Comments