there are 4 white mice and 6 brown mice in a cage. Molly will take out 2 mice at random. If the first mouse she takes out is brown.

a. 2/5

b. 4/9

c.1/2

d.4/5

there are 4 white mice and 6 brown mice in a cage. Molly will take out 2 mice at random. If the first mouse she takes out is brown.

a. 2/5

b. 4/9

c.1/2

d.4/5

Tutors, please sign in to answer this question.

Olney, MD

After taking out the first mouse (a brown one), there are 9 mice remaining in the cage, 4 white ones and 5 brown ones. The probability, then, that the second mouse will be a white one is computed as follows:

P = (Number of White Mice Remaining in the Cage) / (Total Number of Mice Remaining in the Cage)

Let me know what you get.

Willowbrook, IL

Notice that the answer will depend on the manner she takes mice out. If she takes them one after another, then Robert's answer is correct. If she takes both together (with two hands, for example) then the probability is:

6/10*4/9=4/15

Mark D.

Quantitative research SPECIALIST with academic/professional experience

New York, NY

5.0
(148 ratings)

John P.

Tutor of math and physics, recent college graduate

Short Hills, NJ

5.0
(21 ratings)

- Math Help 5396
- Algebra 5026
- Math Word Problem 4435
- Calculus 2188
- Word Problem 5060
- Algebra 2 3444
- Algebra 1 4034
- Math Problem 1010
- Math Help For College 1389
- Math Equations 956

## Comments