there are 8 sweaters, 12 shirts, and 15 pair of pants. how many ways can someone purchase a sweater, 3 shirts and 2 pair of pants?

Question

it is a probability question. I need help 

Answer 1

A sweater can be chosen in ways: 8C1=8

A shirt 12C3 can be chosen in ways: 12C3=(12*11*10)/3!=220 (not that the order of shirts is not important)

A pair of pant 15C2 ways: 15C2=15*14/2 =105

Total number of ways 8*220*105=184800

Feel free to ask any questions!

Answer 2

 a sweater 8 ways

3 shirts 12*11*10 ways

2 pair of pants 15 *14 ways

 

8*(12*11*10)*(15*14)=2217600 ways