J.R. S. answered 02/20/17
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So, the rate of effusion of any ideal gas is inversely proportional to the square root of the molar mass of that gas. This relationship is described by Graham's Law of Effusion which states that ...
rate gas1/rate gas2 = sqrt MW gas2/sqrt MW gas1
Oxygen is O2 and molar mass is 32 g/mol
Hydrogen is H2 and molar mass is 2
Hydrogen being lighter will diffuse faster.
√32 = 5.66
√2 = 1.41
5.66/1.41 = 4.0
So, H2 will diffuse 4 times faster than will O2, or O2 will diffuse at 1/4 the rate of H2 (to answer the question as asked)