Calculate the pressure of 4.61 x 10^ 22 molecules of CO gas mixed with 2.87 x 10^24 molecules of N2 gas in a 5.99 L container at 34.5°C.

Question

How do i do this???

Answer 1

moles CO = 4.61x10^22 molecules x 1 mol/6.02x10^23 molecules = 0.0766 moles CO

moles N2 = 2.87x10^24 molecules x 1 mol/6.02x10^23 molecules = 4.767 moles N2

Total moles of gas = 4.8436 moles

PV = nRT

P = nRT/V = (4.767 moles)(0.0821 Latm/Kmole)(307.5K)/5.99L

P = 20.09 atm = 20.1 atm (to 3 significant figures)