cos^2 x -1/2sin2x=0

Question

find the exact degree values over the given intervals.

0 deg< x < 360 deg

Answer 1

 (Cos X) ^2  - 1/2 sin 2X = 0

 

 

(Cos X) ^2 - sin X Cos X =0

 

  CosX ( CosX - Sin X ) = 0

 

  Cos X = 0       X = 90^°   X = 270°

 

 

   Cos X - Sin X = 0

 

  Tan X = 1    X = 45°    X = 225°