Steve S. answered 02/21/14
Tutor
5
(3)
Tutoring in Precalculus, Trig, and Differential Calculus
A right open bottom cone with a capacity of 250 mL, the radius is 4 cm, what is the volume and the surface area?
1 cc = 1 mL
V = 250 cm^3 = (1/3) B h
B = pi r^2 cm^2
r = 4 cm
250 cm^3 = (1/3) pi 4^2 h
h = 750/(16 pi)
S.A. = pi h^2 * 2 pi 4 / (2 pi h)
S.A. = pi h^2 * 4 / h
S.A. = 4 pi 750/(16 pi)
S.A. = 750/4 =187.5 cm^2