Sam S. answered 01/16/17
Tutor
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Statistical Scientist recognized for teaching as TA
Hi Christopher,
Assuming each carton is an SRS of size 12, the weight of a carton would be normally distributed with mean 12×64.5 g and standard deviation 5.9×√12 g. If X is the weight of a carton and Z is the standard normal random variable,
P(775 < X < 825)
= P((775 - 12×64.5)/(5.9×√12) < Z < (825 - 12×64.5)/(5.9×√12))
= P(0.0489 < Z < 2.4953)
Now you must use a standard normal table or software to compute the probability. Either way your answer will be a decimal approximation, which is why you're being asked to round your answer to four decimal places. You should get an answer slightly less than 0.5.