How many joules of hear are required to raise the temperature of 550g of water from 12.0°C to 18.0°C

Question

Solving for heat  (q) chemistry questions 

Answer 1

Use the formula 

 

Q = mcΔT

 

Q = heat

m = mass of water = 0.550 kg

c = specific heat of water = 4180 J/(kg °C)  (look up in your book)

ΔT = temperature change = 18.0°C - 12.0°C

 

Now just plug in the numbers into the formula and get the heat Q.

 

 

Answer 2

q = mC∆T where q  is heat;  m is mass = 550 g; C is specific heat of water = 4.184 J/g/deg); ∆T is change in temperature = 18-12 = 6º

q = (550 g)(4.184 J/g/deg)(6 deg) = 13,807 J = 13.8 kJ (3 significant figures)