
Steve S. answered 02/16/14
Tutor
5
(3)
Tutoring in Precalculus, Trig, and Differential Calculus
P = D + 0.5 => P - D = 0.5
P + D = 2C + 1.5 => P + D - 2C = 1.5
3P + 3D + 3C = 49.5
Using Augmented Matrix and Row Operations:
R1 = {1,-1,0,0.5}
R2 = {1,1,-2,1.5}
R3 = {3,3,3,49.5}
R1 >> 2 R1
R2 >> 2 R2
R3 >> 2 R3
R1 = {2,-2,0,1}
R2 = {2,2,-4,3}
R3 = {6,6,6,99}
R2 = {2,2,-4,3}
R3 = {6,6,6,99}
R2 >> R2 - R1
R3 >> R3 - 3 R1
R1 = {2,-2,0,1}
R2 = {0,4,-4,2}
R3 = {0,12,6,96}
R2 = {0,4,-4,2}
R3 = {0,12,6,96}
R3 >> R3 - 3 R2
R1 = {2,-2,0,1}
R2 = {0,4,-4,2}
R3 = {0,0,18,90}
R2 = {0,4,-4,2}
R3 = {0,0,18,90}
R2 >> R2/2
R3 >> R3/18
R1 = {2,-2,0,1}
R2 = {0,2,-2,1}
R3 = {0,0,1,5}
R2 = {0,2,-2,1}
R3 = {0,0,1,5}
R2 >> R2 + 2 R3
R1 = {2,-2,0,1}
R2 = {0,2,0,11}
R3 = {0,0,1,5}
R2 = {0,2,0,11}
R3 = {0,0,1,5}
R1 >> R1 + R2
R1 = {2,0,0,12}
R2 = {0,2,0,11}
R3 = {0,0,1,5}
R2 = {0,2,0,11}
R3 = {0,0,1,5}
R1 >> R1/2
R2 >> R2/2
R1 = {1,0,0,6}
R2 = {0,1,0,5.5}
R3 = {0,0,1,5}
R2 = {0,1,0,5.5}
R3 = {0,0,1,5}
{6,5.5,5} grams of fat in piece of pizza at {Pizza Hut,Domino's,Little Caesar's}.
Checked with GeoGebra:
http://www.wyzant.com/resources/files/261883/augmented_matrix_row_ops
The augmented matrix in the GeoGebra solution included an additional 3 columns containing an identity matrix.
So it was [ A | C | I ],
And the result of the reduction to row eschelon form was
[ I | S | A^(-1) ].
So you could solve the system with this matrix equation:
S = A^(-1) C