Given < DAB congruent to < DBA line CD bisects < ADB prove triangle ADC IS CONGRUENT TO TRIANGLE BDC

Question

i have the answer but I want to check my answer bc I think I did it wrong 

Answer 1

triangle ADB

<DAB≅<DBA Given

triangle ADB is isosceles (at least) because an isosceles triangle has 2 congruent angles

therefore AD≅BD The sides opposite the congruent angles are congruent.

CD bisects < ADB Given

<ADC≅<CDB Definition of bisect

triangle ADC≅ triangle CDB by ASA (angle-side-angle)

note: if triangle ADB is isosceles then DC is ⊥ to AB and you could have used the 2 right angles and the AAS postulate