Bill D.

asked • 12/19/16

Prove the identity

prove (1 - cos2x)(1 - tan2x) = sin2x cos2x/1-sin2x
 
I got as far as....
 
Using the left side:
(1 - cos2)(1 - tan2)
(1 - cos2)(1 - sin2/cos2)
1 - cos2 - sin2/cos2 + sin2
 
but now I am stuck

Gene G.

Be careful!  When you copy/paste, superscript formatting gets lost. (I saw your earlier post.)
It should be this:
(1 - cos2x)(1 - tan2x) = sin2x cos2x/1-sin2x
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12/19/16

Bill D.

Fixed it. Thanks
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12/19/16

Gene G.

I don't think the identity is true!
1-cos2x = sin2x
1-sin2x = cos2x
(sin2x)(1-tan2x) = sin2x cos2x/cos2x
1-tan2x=1
0 = tan2x
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12/19/16

Kenneth S.

MIS-PARENTHESIZED nightmare!
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12/19/16

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