equation of a line

Question

What is an equation of a line (in point-slope form) that passes through the points (-2,-3) and (4,3)?

Answer 1

(-2, -3), (4, 3)

 

The point slope form is

y - y₁ = m(x - x₁)

 

m = (difference in y)/(difference in x)

m = [3-(-3)]/[4-(-2)] = 6/6 = 1

 

Use one of the points given for

(x₁, y₁) with m = 1 

Let's use (4, 3)

 

y - 3 = 1(x - 4)

y - 3 = x - 4