The key to this one is drawing out (or, in the absence of a white board, thinking out) the force diagram. First in the y-axis (perpendicular to the incline), we have
Fgy = 11 kg * 9.8 m/s2 * cos(33) = -90.4 N
FN = Fgy = 90.4 N (since the mass isn't sinking into or rising out of the plane)
In the x-axis (parallel to the incline), we have:
Pulling Force: 185N
Ffr = -0.44*90.4N = -39.8 N (negative because friction opposes the pulling force)
Fgx = 11 kg * 9.8 m/s2 * sin(33) = -58.7 N
So, ∑Fx = 185 - 39.8 - 58.7 = 86.5N
Therefore, a = F/m = 86.5N / 11kg = 7.86 m/s2.