Ira S. answered 12/07/16
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I'm not sure if there is another way to do this other than trial and error.
I started with a best out of 9 series.
So A has to win 5 games....This looks like
first 5 .6*.6*.6*.6*.6 = .07776
5 out of 6 5C1* .6*.6*.6*.6*.4 *.6 = .15552
5 out of 7 6C2* .6*.6*.6*.6*.4*.4 *.6 = .186624
5 out of 8 7C3 .6*.6*.6*.6*.4*.4*.4 *.6 = .1741824
5 out of 9 8C4 .6*.6*.6*.6*.4*.4*.4*.4 *.6 = .13934592
So this adds to 73.3% which is far off from 90%.
I tried the best out of 15, first to win 8. and the probability A wins is only 78.69%
This sounds like a computer thing, but I don't have one, so I'm doing by what they call brute force!!!
Let's try best out of 29 or the first to 15.
win first 15 = .6^15 = .00047
15 of 16 = 15C1*.6^14*.4^1*.6 = .0028
15 of 17 = 16C2*.6^14*.4^2*.6 = .009
15 of 18 = 17C3*.6^14*.4^3*.6 = .0205
15 of 19 = 18C4*.6^14*,4^4*.6 = .0368
15 of 20 = 19C5*.6^14*.4^5*.6 = .056
15 of 21 = 20C6*.6^14*.4^6*.6 = .0746
15 of 22 = 21C7*.6^14*.4^7*.6 = .0896
15 of 23 = 22C8*.6^14*.4^8*.6 = .0985
15 of 24 = 23C9*.6^14*.4^9*.6 = .1007
15 of 25 = 24C10*.6^14*.4^10*.6 = .0967
15 of 26 = 25C11*.6^14*.4^11*.6 = .0879
15 of 27 = 26C12*.6^14*.4^12*.6 = .0762
15 of 28 = 27C13*.6^14*.4^13*.6 = .0633
15 of 29 = 28C14*.6^14*.4^14*.6 = .0506
And unfortunately, this only adds up to 86.32%.... so it's higher than the best out of 29....I'll leave the rest to you.
Hope this helped.