Find both solution between 0 degrees and 360 degrees of the equation sin theta =-3/4. Could anyone help me with this because i'm stuck. thanks

Question

Trigonometry

Answer 1

sin θ = -3/4, sin θ < 0 in QIII and QIV.

sin^-1 3/4 = 48.59°    reference angle

sin θ = -3/4 for θ = 180° + 48.59° and θ = 360° - 48.59°