Emma L. answered 12/02/16
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Hi Josh,
First thing we need to do here is create some equations that represent this word problem. Let's call "x" the account that pays 3% interest, and "y" the account that pays 6.25% interest.
2 savings accounts that total $2475 can be represented by: X + Y = 2475
Next, the interest accumulated by the account X = X(0.03)
and, the intestest accumulate by the account Y = Y(0.0625)
Now the total interest accumulated in one year between these two accounts was $116.25 so we can add together our two equations for interest from X and Y:
0.03X + 0.0625Y = 116.25
Now let's solve for X:
First, rearrange the first equation so that you may put Y in terms of X:
X + Y = 2475 becomes..... Y = 2475 - X
Let's substitute our Y into the summated interest equation.
0.03X + 0.0625(2475-X) = 116.25
Simplifying and combining terms are as follows:
0.03X + 154.69 - 0.0625X = 116.25
Subtract 154.69 from both sides:
0.03X - 0.0625X = -38.44
-0.0325X = -38.44
X = 1182.77 (rounded)
Solving for Y:
Y = 2475 - X
Y = 2475 - 1182.77 = 1292.23
Lastly, we should check our work by plugging X and Y back into our original interest equation:
0.03(1182.77) + 0.0625(1292.23)
35.48 + 80.77 = 116.25
Thus the account with 3% interest has a balance of $1182.77 and the account with 6.25% interest has a balance of $1292.23.
Emma L.
12/02/16