College Algebra

Question

Find the [H₃O⁺] for each substance with the given pH

 

drinking water 6.5

Answer 1

Hello, thank you for taking the time to post your question!

The underlying formula that you want to use on this one is

[H3O+] = 10^(-pH)

Meaning that for a pH of 6.5 that becomes

[H3O+] = 10^(-6.5)

=3.16 x 10^(-7) M

I hope that helps you get moving in a better direction on this type of question! Feel free to reach out if you have any additional questions beyond that :)

Answer 2

pH = -log[H₃O⁺]

 

pH = 6.5

 

log[H₃O⁺] = -pH

 

[H₃O⁺] = 10^-pH = 10^-6.5 ≅ 3.162 x 10^-7